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LT3008 データシートの表示(PDF) - Linear Technology

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LT3008 Datasheet PDF : 16 Pages
First Prev 11 12 13 14 15 16
LT3008
APPLICATIONS INFORMATION
The following tables list thermal resistance for several
different board sizes and copper areas. All measurements
were taken in still air on 3/32" FR-4 two-layer boards with
one ounce copper.
PCB layers, copper weight, board layout and thermal vias
affect the resultant thermal resistance. Although Tables
2 and 3 provide thermal resistance numbers for 2-layer
boards with 1 ounce copper, modern multi-layer PCBs
provide better performance than found in these tables.
For example, a 4-layer, 1 ounce copper PCB board with
3 thermal vias from the DFN exposed backside or the
3 fused TSOT-23 GND pins to inner layer GND planes
achieves 45°C/W thermal resistance. Demo circuit DC
1388A’s board layout achieves this 45°C/W performance.
This is approximately a 30% improvement over the lowest
numbers shown in Tables 2 and 3.
Table 2: Measured Thermal Resistance for DC Package
COPPER AREA
TOPSIDE*
2500mm2
BACKSIDE
2500mm2
BOARD
AREA
2500mm2
THERMAL RESISTANCE
(JUNCTION-TO-AMBIENT)
65°C/W
1000mm2 2500mm2 2500mm2
70°C/W
225mm2
100mm2
2500mm2
2500mm2
2500mm2
2500mm2
75°C/W
80°C/W
50mm2
2500mm2 2500mm2
85°C/W
*Device is mounted on the topside.
Table 3: Measured Thermal Resistance for TSOT-23 Package
COPPER AREA
TOPSIDE*
2500mm2
BACKSIDE
2500mm2
BOARD
AREA
2500mm2
THERMAL RESISTANCE
(JUNCTION-TO-AMBIENT)
65°C/W
1000mm2 2500mm2 2500mm2
67°C/W
225mm2 2500mm2 2500mm2
70°C/W
100mm2 2500mm2 2500mm2
75°C/W
50mm2
2500mm2 2500mm2
85°C/W
*Device is mounted on the topside.
Calculating Junction Temperature
Example: Given an output voltage of 3.3V, an input volt-
age range of 12V ±5%, an output current range of 0mA
to 20mA and a maximum ambient temperature of 85°C,
what will the maximum junction temperature be for an
application using the DC package?
The power dissipated by the device is equal to:
IOUT(MAX) (VIN(MAX) – VOUT) + IGND (VIN(MAX))
where,
IOUT(MAX) = 20mA
VIN(MAX) = 12.6V
IGND at (IOUT = 20mA, VIN = 12.6V) = 0.3mA
So,
P = 20mA(12.6V – 3.3V) + 0.3mA(12.6V) = 189.8mW
The thermal resistance ranges from 65°C/W to 85°C/W
depending on the copper area. So the junction temperature
rise above ambient approximately equals:
0.1898W(75°C/W) = 14.2°C
The maximum junction temperature equals the maximum
junction temperature rise above ambient plus the maximum
ambient temperature or:
TJ(MAX) = 85°C + 14.2°C = 99.2°C
3008f
11

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