ADL5570-EVALZ データシートの表示（PDF） - Analog Devices
部品番号
コンポーネント説明
一致するリスト
ADL5570-EVALZ Datasheet PDF : 12 Pages
| |||
64 QAM OFDMA PERFORMANCE
The ADL5570 shows exceptional performance when used with
a higher order modulation scheme, such as a 64 QAM system.
Figure 13, Figure 14, and Figure 15 illuminate the EVM, gain,
and current consumption performance within the context of
a 64 QAM OFDMA system.
19
18
17
16
15
2350MHz
14
13
12
11
2400MHz
10
9
8
7
6
5
4
3
2300MHz
2
1
0
0
5
10
15
20
25
30
35
POUT (dBm)
Figure 13. EVM vs. POUT Performance at
VCC = 3.5 V and 64 QAM OFDMA Signal
32
31
30
29
28
2280
2300
2320
2340
2360
2380
2400
2420
FREQUENCY (MHz)
Figure 14. Gain vs. Frequency Performance at
VCC = 3.5 V and 64 QAM OFDMA Signal
ADL5570
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
0
5
10
15
20
25
30
35
POUT (dBm)
Figure 15. Burst Current vs. POUT at VCC = 3.5 V, 64 QAM,
2350 MHz, 31% 802.16e OFDMA Signal
POWER-ADDED EFFICIENCY
The efficiency of the ADL5570 is defined on the current that it
draws during the data burst of an 802.16e OFDMA signal. In
typical test setup, the average rms current, IAVG, is measured.
However,
IAVG = Duty Cycle (in decimal) × IBURST +
(1 − Duty Cycle [in decimal]) × IDEFAULT
where:
IBURST is the rms current during the data burst of an
OFDMA signal.
IDEFAULT can be the quiescent current drawn when there is no
data burst and the device remains biased, the sleep current
(1 mA) if the device is defaulted to sleep mode, or the
standby current.
For example, in a 31% duty cycle 802.16e OFDMA signal,
the burst current is calculated by rearranging the previous
equation to get
I BURST
=
(Ι AVG
− 0.69 × IDEFAULT )
0.31
Finally, the PAE is calculated by
RF Output Power (mW) − RF Input Power (mW)
PAE (%) =
× 100
VCC (V) × IBURST (mA)
When RF = 2.35 GHz, 31% 16 QAM OFDMA signal,
VCC = 3.5 V, RF output power = 25 dBm, and RF input
power = −4 dBm, the ADL5570 consumes a burst current,
IBURST = 450 mA and PAE = 21%.
Rev. 0 | Page 9 of 12
Share Link: 