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NCP1027 データシートの表示(PDF) - ON Semiconductor

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NCP1027 Datasheet PDF : 30 Pages
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NCP1027
Figure 25. A typical startup sequence showing the VCC capacitor
voltage evolution versus time.
Suppose our power supply takes 10 ms (tstartup) to bring
the output voltage to its target value. We know that the
switcher consumption is around 2.0 mA (ICC1). Therefore,
we can calculate the amount of capacitance we need, to
hold VCC above 7.5 V at least for 10 ms while delivering
2.0 mA:
C
w
ICC1tstartup
DVCC
or,
by
replacing
with
the
above
values,
C
w
2m
· 10
1
m
w
20
mF
then
select
a
33
mF
for
the
VCC
capacitor.
Fault Condition – Short−Circuit on VCC
In some fault situations, a short−circuit can purposely
occur between VCC and GND. In high line conditions
(VHV = 370 VDC) the current delivered by the startup
device will seriously increase the junction temperature. For
instance, since IC1 equals 3.0 mA (the min corresponds to
the highest TJ), the device would dissipate 370 3 m =
1.1 W. To avoid this situation, the controller includes a
novel circuitry made of two startup levels, IC1 and IC2. At
powerup, as long as VCC is below a 1.3 V level, the source
delivers IC1 (around 650 mA typical), then, when VCC
reaches 1.3 V, the source smoothly transitions to IC2 and
delivers its nominal value. As a result, in case of
short−circuit between VCC and GND, the power dissipation
will drop to 370 650 m = 240 mW. Figure 26 portrays
this particular behavior.
Figure 26. The startup source now features a
dual−level startup current.
The first startup period is calculated by the formula
C V = I t, which implies a 33 m 1.3/650 m = 66 ms
startup time for the first sequence (t1). The second
sequence (t2) is obtained by toggling the source to 4.0 mA
with a delta V of VCCON – VCCth = 8.5 – 1.5 = 7.0 V,
which finally leads to a second startup time of
7 33 m/6.0 m = 39 ms. The total startup time becomes
66 m + 39 m = 105 ms as a typical value. Please note that
this calculation is approximated by the presence of the knee
in the vicinity of the transition.
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