ADL5571-EVALZ データシートの表示（PDF） - Analog Devices
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ADL5571-EVALZ Datasheet PDF : 16 Pages
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ADL5571
64 QAM OFDMA PERFORMANCE
The ADL5571 shows exceptional performance when used with
a higher order modulation scheme, such as a 64 QAM system.
Figure 22, Figure 23, and Figure 24 illuminate the EVM, gain,
and current consumption performance within the context of a
64 QAM OFDMA system.
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13
12
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10
9
8
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5
4
2700MHz
2500MHz
3
2
1
2600MHz
0
8 10 12 14 16 18 20 22 24 26 28
POUT (dBm)
Figure 22. EVM vs. POUT Performance at VCC = 3.3 V and
64 QAM OFDMA Signal
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31
30
29
28
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26
2500 2520 2540 2560 2580 2600 2620 2640 2660 2680 2700
FREQUENCY (MHz)
Figure 23. Gain vs. Frequency Performance at VCC = 3.3 V and
64 QAM OFDMA Signal
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
0
5
10
15
20
25
30
POUT (dBm)
Figure 24. Burst Current vs. POUT at VCC = 3.3 V, 64 QAM,
2350 MHz, 31% 802.16e OFDMA Signal
POWER-ADDED EFFICIENCY
The efficiency of the ADL5571 is defined on the current that it
draws during the data burst of an 802.16e OFDMA signal. In
typical test setup, the average rms current, IAVG, is measured.
However,
IAVG = Duty Cycle (in decimal) × IBURST +
(1 − Duty Cycle [in decimal]) × IDEFAULT
where:
IBURST is the rms current during the data burst of an OFDMA
signal.
IDEFAULT can be the quiescent current drawn when there is no
data burst and the device remains biased, the sleep current
(<1 μA) if the device is defaulted to sleep mode, or the standby
current.
For example, in a 31% duty cycle 802.16e OFDMA signal,
the burst current is calculated by rearranging the previous
equation to get
I BURST
=
(Ι AVG
− 0.69 × IDEFAULT )
0.31
Finally, the PAE is calculated by
PAE (%) =
RF Output Power (mW) − RF Input Power (mW)
× 100
VCC (V) × IBURST (mA)
When RF is 2.6 GHz, 31% 16 QAM OFDMA signal,
VCC is 3.3 V, RF Output Power is 25 dBm, and RF Input
Power is −4 dBm, the ADL5571 consumes a burst current,
IBURST is 450 mA and PAE = 21%.
Rev. 0 | Page 12 of 16
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